Hypothesis Testing Review –
ce department’s claim
o 𝜇 150.00𝜇 > 150.00
𝑡 =̅
√
𝑡 = .√
, 159 2.35
p .0022
el of significance the evidence supports the police department’s
o 𝜇 = 15𝜇 ≠ 15
𝑡 =̅
√
𝑡 =..
√
2.118
20 2.093
p p
ibutions from a university’s alumni and supporters is considered
o 𝑝 ≥ .15𝑝 < .15
�̂� = �̂� =_= .16
𝑧 =( )
𝑧 =. .
. ( . )0.443
1.645
p 06710.0.6710
o 𝜇 = 𝜇𝜇 ≠ 𝜇
𝑡 =( ̅ ̅ ) ( )
𝑡 =( . ) ( )
. .
25, 29
p 0.12250.1225
6
4
o 𝜇 ≤ 𝜇𝜇 > 𝜇
𝑡 =( ̅ ̅ ) ( )
𝑧 =( . . ) ( )
. .0.797
5 1 1.48
p
There is not sufficient evidence to say that there is a reduction in Gary’s mean time
o
1010 980 1170 1200 1040 1280 1450 1470 15001100 1260 1190 1280 1170 1370 1440 1500 152090 280 20 80 130 90 10 30 20
o 𝜇 ≤ 60𝜇 > 60
𝑡 =√
𝑡 =.
.
√
.780
9 2.896
p 0.23040.2304
o 𝑝 ≥ 𝑝𝑝 < 𝑝
�̂� = �̂� = �̂� = = .75
�̅� = = = .74
𝑧 =( ) ( )
̅( ̅)( )𝑧 =
(. . )
. ( . )( )
1.43
1.64
p 1.64
university’s claim that the retention rate improved
manager’s claim using 0.10 level of significance. The owner surveyed 739 customers over a period of time to record each customer’s preferred day of the week. Here’s what he found.
103 103 126 103 111 96 97
o 𝑝 = 𝑝 = 𝑝 = 𝑝 = 𝑝 = 𝑝 = 𝑝
o 2 (𝒐 − 𝒆)𝟐
𝒆103 2.57 6.6122 .0626103 105.71 2.57 6.6122 .0626126 105.71 20.429 417.33 3.953103 105.71 2.57 6.6122 .0626111 105.71 5.4286 29.469 .2791496 105.71 9.571 91.612 .8677797 105.71 9.571 73.469 .69592
� 5.984
7 ––
2 10.645 From x2
p
At the .10 level of significance the evidence does not support the manager’s claim
15 29 94 102 105 30130 44 99 97 86 28245 59 68 73 76 217
261 272 267 800Expected Values
15 29 30130 44 28245 59 217
261 272 267 800
o
–
2 ( ) ( . )
.
( . )
.
( . )
.
( . )
.
( . )
.( . )
.
( . )
.
( . )
.
( . )
.1.927
2
p 0.7492
